Friday, October 14, 2011
Tuesday, July 26, 2011
Vels University on facebook
Hi friends i have created vels university page on facebook.... just follow join
http://www.facebook.com/pages/Vels-University/195611110496402?v=wall
http://www.facebook.com/pages/Vels-University/195611110496402?v=wall
Monday, July 18, 2011
kalvarayan hills on 16.7.2011
kalvarayan hills on 16.7.2011
Wednesday, July 13, 2011
TCS Placement Papers - Solved Quantitative Aptitude Question
Below you can find three sample questions compiled on the model of TCS Placement Papers.
You may expect such questions on TCS Placement Papers as well as Technical Interview of TCS.
Refer for more TCS Placement Papers
1) In a 300 m race A beats B by 22.5 m or 6 sec.What is the
B's time over the course?
Sol: B runs 22.5 m in 6sec.
B runs 300m in =6*300*2/45 =80 sec.
B's time over the course =80 sec.
Top
2) A can run 22.5 m while B runs 25 m.In a kilometre race B
beats A by?
Sol: B runs 25 m ,A runs 45/2 m B runs 1000 A runs
= 1000*45/2*25 =900m B beats A by 100m
3)In a 500 m race, the ratio of the speeds of two contestants
A and B is 3:4.A has a start of 140 m.Then ,A win by B?
Sol: The speeds of A and B =3:4 To reach the winning post A will
have to cover a distance of 500-140 m i.e 360 m while A covers 3m,
b covers 4m A covers 360m B covers 4/3*360=480m Thus when A
reaches the winning post, b covers 480m and therefore remains
20m behind. A wins by 20m.
You may expect such questions on TCS Placement Papers as well as Technical Interview of TCS.
Refer for more TCS Placement Papers
1) In a 300 m race A beats B by 22.5 m or 6 sec.What is the
B's time over the course?
Sol: B runs 22.5 m in 6sec.
B runs 300m in =6*300*2/45 =80 sec.
B's time over the course =80 sec.
Top
2) A can run 22.5 m while B runs 25 m.In a kilometre race B
beats A by?
Sol: B runs 25 m ,A runs 45/2 m B runs 1000 A runs
= 1000*45/2*25 =900m B beats A by 100m
3)In a 500 m race, the ratio of the speeds of two contestants
A and B is 3:4.A has a start of 140 m.Then ,A win by B?
Sol: The speeds of A and B =3:4 To reach the winning post A will
have to cover a distance of 500-140 m i.e 360 m while A covers 3m,
b covers 4m A covers 360m B covers 4/3*360=480m Thus when A
reaches the winning post, b covers 480m and therefore remains
20m behind. A wins by 20m.
Tuesday, July 12, 2011
Tcs Placement qustions
TCS Placement Papers Solved Aptitude Question
held on januray 2011 ......
Follow the link
http://way2freshers.com/placement-papers/tcs-papers/tcs-solved-placement-paper-held-on-5th-jan-2011.html
Aptitude test
Hi this is Chan Anand
Here I would like to share my memories.....
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